0=32400-1800x+24x^2

Solution for 0=32400-1800x+24x^2 equation:

0=32400-1800x+24x^2

We move all terms to the left:

0-(32400-1800x+24x^2)=0

We add all the numbers together, and all the variables

-(32400-1800x+24x^2)=0

We get rid of parentheses

-24x^2+1800x-32400=0

a = -24; b = 1800; c = -32400;
Δ = b2-4ac
Δ = 18002-4·(-24)·(-32400)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1800)-360}{2*-24}=\frac{-2160}{-48}
=+45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1800)+360}{2*-24}=\frac{-1440}{-48}
=+30
$